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Simplifying 5b2 + 50b + -120 = 0 Reorder the terms: -120 + 50b + 5b2 = 0 Solving -120 + 50b + 5b2 = 0 Solving for variable 'b'. Factor out the Greatest Common Factor (GCF), '5'. 5(-24 + 10b + b2) = 0 Factor a trinomial. 5((-12 + -1b)(2 + -1b)) = 0 Ignore the factor 5.Subproblem 1
Set the factor '(-12 + -1b)' equal to zero and attempt to solve: Simplifying -12 + -1b = 0 Solving -12 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1b = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1b = 0 + 12 -1b = 0 + 12 Combine like terms: 0 + 12 = 12 -1b = 12 Divide each side by '-1'. b = -12 Simplifying b = -12Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2Solution
b = {-12, 2}
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